40=12t+-5t^2

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Solution for 40=12t+-5t^2 equation: 



40=12t+-5t^2

We move all terms to the left:

40-(12t+-5t^2)=0

We use the square of the difference formula

-(12t-5t^2)+40=0

We get rid of parentheses

5t^2-12t+40=0

a = 5; b = -12; c = +40;
Δ = b2-4ac
Δ = -122-4·5·40
Δ = -656
Delta is less than zero, so there is no solution for the equation

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